What is the sum of positions assigned to brom | vedclass

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(C) According to $IUPAC$ nomenclature rules for cyclic compounds containing a double bond,the double bond is given priority and assigned positions $1$

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) According to $IUPAC$ nomenclature rules for cyclic compounds containing a double bond,the double bond is given priority and assigned positions $1$ and $2$. For compound $(I)$,the bromine is at position $6$. For compound $(II)$,the bromine is at position $3$. For compound $(III)$,the bromine is at position $1$. For compound $(IV)$,the bromine is at position $5$. Sum of positions $= 6 + 3 + 1 + 5 = 15$.

What is the sum of positions assigned to bromine $(Br)$ while numbering the parent chain in the given compounds?

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